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Lumenlab > Audio Video Sciences > Projector Builder > Projector Technical Support
Tha
Hi
I have a question for ya
Whats the lenght og the screen, if its 4:3 and 85" diag, ?
pagercam
a^2 + b^2 = c^2

classic case is the 3:4:5 triangle

so 5 = 85"
85/5 = 17"
width (4) = 17*4 = 68"
height (3) = 17" *3 = 51"

Can't anyone do basic math anymore???
bevo77
QUOTE (pagercam @ Jan 16 2006, 03:19 AM) *
a^2 + b^2 = c^2

classic case is the 3:4:5 triangle

so 5 = 85"
85/5 = 17"
width (4) = 17*4 = 68"
height (3) = 17" *3 = 51"

Can't anyone do basic math anymore???

Does your formula adjust for keystoning?
pagercam
QUOTE (bevo77 @ Jan 16 2006, 10:59 AM) *
Does your formula adjust for keystoning?

What does the size of the screen have to do with keystone???
Mikau
Screen size has nothing to do with keystoning. You just adjust the projectors position closer or farther after adjusting. IF you want to keep the projector a certain distance from the screen, regardless of keystoning, then size would be a function of how far you want it and the degree of keystoning. Thats a bit more complicated. Solvable, but I bet thats not what you want anyways. My screen size is about 6 feet wide. Its a pull down screen so the height is adjustable.

Hey pagercam! I can do basic math! Watch this:

x = y

x^2 = xy squared both sides

x^2 - y^2 = xy - y^2 added y^2 to both sides (additive property of equality)

(x+y)(x-y) = y(x - y) factored

x + y = y divided both sides by (x - y)

Let x = 1, x = y so y = 1:

1 + 1 = 1.

2 = 1 biggrin.gif
bevo77
QUOTE (pagercam @ Jan 16 2006, 02:10 PM) *
What does the size of the screen have to do with keystone???

It was lame attempt at humor.
Mikau
QUOTE
What does the size of the screen have to do with keystone???


QUOTE (bevo77 @ Jan 16 2006, 09:20 PM) *
It was lame attempt at humor.


Why is everyone talking like rox? huh.gif
pagercam
QUOTE (bevo77 @ Jan 16 2006, 12:20 PM) *
It was lame attempt at humor.

Its only a joke if other people get it.
Mikau
QUOTE (pagercam @ Jan 16 2006, 09:37 PM) *
Its only a joke if other people get it.


Yeah I can't see how thats even hypathetically a joke.
Rox
well, wana now where is your mistake mikau? biggrin.gif

(you can talk like me but, please do not make so many mistakes... biggrin.gif:D)
Mikau
Yeah I know where the mistake is. x = y. so x - y = 0. Towards the end we divided both sides by x-y which is zero.

Basicly we had 2*0 = 1*0 which is true, but we cancelled out the zero's to get 1 = 2. One of the many reasons division by zero is not permissable.
Rox
ouch! (read as homer simpson's typical sound)

;D
Mikau
Here you go rox. I did this one yesterday.

Find the value of r where dA/dr = 0:
RymGB
QUOTE (Mikau @ Jan 18 2006, 08:14 AM) *
Find the value of r where dA/dr = 0:

Still no answer... could someone please post an answer... this is starting to mess with my emotions sad.gif .

Is it r = 4.07 ??
scubasteve2365
QUOTE (Mikau @ Jan 17 2006, 09:14 PM) *
Here you go rox. I did this one yesterday.

Find the value of r where dA/dr = 0:


ewww. Its been quite awhile since Ive had Cal, soooo ... lets just keep the derivitaves elsewhere....

LOL @ Mikau for wanting to do Calculus in his free time ...... biggrin.gif
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