QUOTE (vincent666 @ Aug 23 2008, 05:47 AM)

Hi electrodacus,
i take long time to take a look i your wonderful job...
I interesting to insert led into my beamer (sanyo Z2, infocus LP130)
first i know that for dlp projector i need to concentrate the light on one point
just before the color wheel and for 3 LCD i need to have a "box of light".
I have buy from dealextreme the 20w led with 800 lumens but i
have found other led with 20w and 1400 lumens...(but it is
not disponible for the moment)
My problem is how you can have a power for 3,6v at 4 or 5 Amp
(to have one or two led at 20w)
i have found that this man use a soul P7 with 900lumens but
i don't understand how they do with a laptop adaptator to
have 3,6volt output...(because there is not laptop power
with a output at 3,6v).
http://cgi.ebay.fr/videoprojecteur-BenQ-MP...3QQcmdZViewItem Excuse me for my poor english, i'm from france.
If you could help me for this point i would greatly appreciate
because it blocked me to go farther.
Again you have done great and very very interesting job.
best regards,
Vincent.
For LED's you do not care to much about the Voltage the most important parameter is max current 2.8A (4x700mA 4led connected in paralleled) for the P7 so you need a power supply than can deliver 2.8A or more and you need to limit the current to 2.8A or less for this LED to limit the current the easiest way is to use a resistor in series with the LED and the value of this resistor need to be calculated the formula will be R = Vpowersupply - Vmaxled / current
I will give you 2 example:
EX1:
Vpowersupply = 12V
Vmaxled = 3.6V
current = 2.8A
then R= 12-3.6/2.8 so R = 3 ohm
but you need a big Resistor because the power loss on the resistor will be Presistor=Vresistor * current
Vresistor = Vpowersupply - Vmaxled so Vresistor= 12-3.6 Vresistor=8.4V
Presistor = 8.4 * 2.8 = 23.52W this is a lot of power you will not find to easy a resistor of 25W or more (you can use more smaller resistor )
EX2:
Vpowersupply = 5V
Vmaxled = 3.6V
current = 2.8A
then R= 5-3.6/2.8 so R = 0.5 ohm
but you need a big Resistor because the power loss on the resistor will be Presistor=Vresistor * current
Vresistor = Vpowersupply - Vmaxled so Vresistor= 5-3.6 Vresistor=1.4V
Presistor = 1.4 * 2.8 = 3.92W this is still a lot of power you will be able to find a 5W resistor or more (you can use more smaller resistor )
I used the same LED in EX1 and EX2 with the same current so also the same light output but in first example the power consumption will be 10W led + 23.5W resistor so a total of 33.5W and in EX2 10W + 3.92W so a total of 13.92W .
These are some example just to understand that for LED the most important parameter is current if you limit this you get also the right voltage on LED.
using Resistor is not the best idea but is the easiest thing to do.
There are some special drivers for LED that use more components like transistors, capacitors and coils and have much better efficiency than using just resistors.
I hope I was not to confusing

If you search on the internet about LED drivers you will find more .