not laughing at all... confirms what others have said, and what the challenge is. Your results are consistent with the numbers I've seen thrown around for light transmission and collimation requirements in DIY PJs:... can't remember where I saw all these numbers here, but they are good enough for a rough estimate:
biggest consideration for fluorescents: ~7 degree within field fresnel normal to make it through triplet (i.e. collimated light)
fresnel transmission: 95%
LCD transmission (depends a bit on lamp's spectral power distribution and how well it matches the lcd's color filter: 6-9% for HID bulbs, 12-13% for fluorescent (can't remember where i saw these)
triplet transmission: 75%
So, to estimate what I thought you should get, I just multiply all the transmissive factors together, and make an estimate of the amount of collimated light you're likely to get with the setup you have. First the transmission of collimated light:
LCD*fieldFresnel*triplet = 0.12*0.95*0.75=8.5%, so no matter what it looks like behind the LCD, you will not get more than 8.5% of the lumens on screen. But 8.5% of 16K is nearly 1500 lumens, that would be nice!
The problem is the amount of diffuse light we can get collimated before passing through the field fresnel.
Given that light exits a fluorescent lamp from all points and in all directions, the light exiting a bulb within a +/-7 degree cone is: (14/360)^2=0.15% (ouch). So, without reflection, you would get... 8.55%*0.15%*16000 = 2 lumens.
Neglecting reflection losses, and you should get about 4X this because you have three additional bulb images (one off each side reflector and one off the rear reflector). This is a bit optimistic in that it neglects losses due to light passing through the bulbs. Anyway with all the above factors and simplifications, you should be getting: 16000*.0855*((1+3*.95)*(14/360)^2 = 7.965 lumens. Are you sure your meter is working properly

You will get more light with your new design (more reflections that lead to a 14 degree cone of collimated light), but really need to collimate a significantly higher percentage of light to get what most would consider a usable projector. Look at it this way... if you could get 10% of that output collimated, you'd have a 140 lumen projector. getting that 10% is REALLY difficult though in a reasonably sized enclosure. Another approach would be to place the highest output, slimmest bulb you can find in a VERY long light tunnel (widening from the bulb width at the back to the screen width at the other end. I've played around alot with different bulbs and geometries with this idea in a spreadsheet, and I'm currently leaning toward a single 42W 3U 4-pin compact fluorescents in a 5 foot long divergent reflecting tunnel (similar to your multiple reflectors, just deeper and with much shallower divergence creating many more reflections and ultimately collimating a much higher percentage of light. I estimate I can get about 60% of the light collimated (nearly 2000 lumens)... if I get anywhere near that, I have a usable projector consuming less than 50W. My biggest concerns are vignetting (due to a single bulb without overlapping high/low areas from multiple bulbs) and hotspotting due to the difficulty of laying the reflective mylar cleanly over such a large area. Funds and time are in short supply right now, so I will not really get started on this for another month or two. Please try it out and prove me wrong if you feel so inclined

QUOTE (daveoxide @ Mar 27 2008, 06:27 PM)

ROFL!! I took some lux measurements... make sure you are sitting down otherwise you will fall down from laughing so hard...
Lux Measurements 27-Mar-08
3.3 5.0 3.2
4.0 6.5 3.8
3.3 4.6 3.2
Room Lux = 1.6
Avg. Lux = 2.5
Area (m) = 2.9
Lumen = 7.25
So yeah, that really sucks! Thank goodness I have a trick up my sleeve to hopefully double the brightness over the weekend (that isn't really saying much, lol). I'll post more results when I have them.