While searching trough my lots of junk, stuff, in the garage i found an almost brand new car stereo wich, of course has 4 4Ohm FL FR RL RR (front left, front right, rear left, rear right)outputs.

I understand that when connecting speakers in series you add the total impedance of the speakers: 8 Ohm Speaker + 8 Ohm Speaker = 16 Ohm total impedance.

While in parallel it is Ohms / number of speakers, so: 8 Ohm speaker / lets say two speakers u get 4Ohm total impedance. If thats right.. then..

Can you then use two 8ohm speakers in parallel and plug them??

What about making it even better ( i think ) and plug both into lets say the RL + FL outputs? picture's worth a thousand words so..




Sorry im a total noob when it comes to audio..!!

Cheers.

Hooking it up like in your diagram will probably burn up your stereo. Just hook them up as if they were 4 ohms. The only effect will be lower power.

Do not short the output speakers leads from the head unit, it will burn it out.

Unless you drive around with the volume at 3/4 all the time you may not notice the lower sound level. You will get less distortion with the 8 ohm driver.

Arkcom is correct. It's only when you go under the specified impedance that you risk cooking your amp and speakers for that matter, as you will have increased current flowing through the speakers and in and out of the amp. Higher impedance gives reduced current flow, but also in turn reduced power.

On a bit of a tangent, if you have a high end house amp, some of them have a selection of impedances for speakers which you can select to optimise power output.

Bevan

Oh..! Thank you all for the answers! ill hook it up right now

Alex.

When in parallel it is actual xy/x+y. So 8(8)/8+8 or 64/16=4. So with an 8 ohm and a 4 ohm speaker it would be 8(4)/8+4 or 32/12=2.66

See