Ill need a IR/UV filter in my next projector and I found to.

The one from http://www.exclusiv-online.com.

90x90 mm and 2 mm thick. 26 euros. Total cost 43 euro's (with sending fee).

3. IR/UV glass filter SKGF blocks not only UV rays (A-B-C) which are responsible for the fading of the polarization foil, but also an immense part the infrared rays. The IR-rays are responsible for the heating process of further components as well as TFT panel. With this filter your display will stay in right temperatures (3 or more fans no more needed - only one)

And the one from http://www.emils-beamershop.de.vu/.
24 x 32 cm. 24 euros. Total cost (with sending fee) 34,80 euro.

All IR/UV glasses are manufactured glasses a based on DIN.
The IR layer consists of a vacuum-metalized argentic layer. The argentic layer (moistened with saliva it shimmers lilac) is electroconductive (commensurable with an ohmmeter).
Please do not use a metal frame.Please do not place it nearer than 12cm to the burner(400 watt).
Please clean it with a soft cloth or a glass cleaner.

Borofloat glass:color neutral and by elimination of ferrous oxide improved Floatglass.
transmission ~93.5%

At the moment ill go with the Emils one, because its 10 euos cheaper and a lot bigger.
But before I order what are you thoughts on it?

Greetings Peter Boomsma

So.. 20 views but no comments

The specs on the webpage look reasonable. Do you have specific questions to address or are you just seeking assurances that you are not making a mistake?

I remember reading somewhere that there are 2 popular ways of manufacturing ir/uv mirrors... one is a coating and the better one is a vaccum seal of some sort... of which I believe the borofloat is...

I'm not sure on this though...

The specs to check for uv/ir mirrors are

• % visible light transmissiveness (more is better)
• % IR light transmissiveness (less is better)
• size
• method of coating
• distance from source

the 12cm marked on the borofloat is quite large... so yes it's a bigger and cheaper piece, but you might have to place it farther away from the bulb than the 90x90...

so in short... i would find out more or as much as you can about both.

to computer the size of the light cone you can use the similar triangles equation...
of which DaveT3000 explained in my plog... here http://www.lumenlab.com/forums/index.php?s...st&p=162134

hope this helps.

i feel like i should go computer something...


sorry i hate spelling mistakes, especially my own.