QUOTE (PLJack @ Aug 4 2006, 05:08 PM)

Very cool, can't wait for you to start.
I'm not clear on what your total LED count is. 918?
918 x 20ma = 18360ma / 1000 = 18.36 amps. Yes?
Either way you probably should blink each row, thus the circuit will only see the amperage for one row.
You can use a $3 Parallax SX chip to blink the rows so fast that you would not notice the blinking.
A side effect would be brightness control.
On a side note be very careful of the power a LED sees. Overpowering a LED will not due much for brightness but will reduce its life by a factor of ten or more.
Oh, and good luck.
Well that would be if I did a whole bunch of LEDs in parallel with each one having a resistor. I am instead going to use a 48V (or higher if I can find one) DC power supply. Then arrange the LEDs in a series-parallel method.
Each series will have 13 LEDs (13*3.4V = 44.2V total drop) leaving 3.8V to be dropped on the resistor (180ohm + potentiometer, which I will explain why later) which will limit each series 20mA. So having a whole bunch of these strings in parallel would give me a current divider.
So I would have 71 Series of LEDs, each series needing 20mA, which equals 1.42A total. I would add the 190ohm + potentiometer so I can vary the resistance by 180+-20ohms more, since not all LEDs work alike in real life, and I can fine tune it using a DMM to test the exact current going through and get it to 20mA.
I was actually suprised the other day when testing out a prototype of of the LED array on how big a difference 17mA was compared to giving it 20mA.